01be028a67 Get your hands on every practice test you can - here, Boson, ExamCram, whatever. try to understand the concept. Read each of the questions carefully as I had a couple of different ones but similar in theory. -crossover and straight through, which devices require what type of cable. Therefore there are 24 2 = 14 assignable IP addresses for hosts on the LAN. Sorry, but you're off the map.. IP if given a small network. shellee1983 Member Join Date Mar 2012 Location WA Posts 71 Certifications CEH, Security , A , CCENT 07-01-201309:22 PM #5 Originally Posted by wweboy 1. With half duplex (HDX), you can transmit and receive, but you can only do one of these at a time i.e. Therefore: Increment: 16 (/28=1111 1111.1111 1111.1111 1111.1111 0000) Network address: 192.168.136.0 Broadcast address: 192.168.136.15 (15 = 0 16 1) -> The broadcast address of this subnetwork is 192.168.136.15 Question 2 What is the bandwidth on the WAN interface of Router1? A 16 Kbit/sec B 32 Kbit/sec C 64 Kbit/sec D 128 Kbit/sec E 512 Kbit/sec F 1544 Kbit/sec Answer: E Explanation To find out the bandwidth on the WAN (serial) interface of Router1 we need to use the show interfaces serial 0/0 command: Therefore the bandwidth on the WAN is 512 Kbit/sec.
ACLs have always kicked my butt I understand them but don't understand them. I remembered the last question as The users in the LAN cannot access the web. Quote . Also know how RIP, OSPF, and EIGRP calculate their metric. With full duplex (FDX), you CAN transmit and receive at the same time. I had completed my exam in 35 mins. Which help us to resolve the complicated and tricky questions on net working.
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